The bearing gallery between rotor 4 and the industrial rotor, two huge hubs turning in opposite directions about the stationary axis.

Counter-rotation and momentum

A spinning city is a giant gyroscope, and a gyroscope fights every push that tries to tilt it. Concordia spins its four city rotors in opposite pairs, so the total spin is zero. Two momentum rings take care of the small remainder.

What the tags mean

The gyroscope problem

Hold a spinning bicycle wheel by its axle and try to tilt it. The wheel pushes back sideways. The faster it spins and the heavier it is, the stronger the push. That stubbornness is angular momentum, and the total of it in a closed system never changes. Established physics

Helicopters show the same law at work. The big rotor spins one way, so the body wants to spin the other way. A small tail rotor pushes against it. Without the tail rotor, the cabin would turn in circles.

Now scale up. Each Concordia rotor has a mass of about 300 billion kg and turns once every 100 seconds at a radius of 2,500 m. One rotor holds about 1.2 × 10¹⁷ newton-metre-seconds of angular momentum. Four rotors spinning the same way would hold 4.7 × 10¹⁷. A station with that much spin cannot simply turn to face a new direction. Pointing it at anything would take a continuous push of 4.5 million newtons at each end of the hull, for every degree per day. Established physics

The whole station with the rotational frame overlay: spin direction labels for the four rotors and the 100 second turn.
The rotational-frame overlay: each rotor turns once in 100 seconds, with a rim speed of 157 m/s. The labels already show the way out: two rotors turn one way and two the other. Open this view in the simulation

Spin pairs

Concordia cancels the problem instead of fighting it. Seen from the spaceport end, Tsiolkovsky and Noordung (Rotors 1 and 2) turn one way (retrograde) and Bernal and O'Neill (Rotors 3 and 4) turn the other (prograde). Each spin pair holds half the total, one negative and one positive, so the habitation rotors add up to zero by construction. Design value

Spin pairs and momentum along the station axis Side view along the 21 km axis, aft on the left. Rotors 1 and 2 spin retrograde and together hold minus 50 percent of the four-rotor angular momentum. Rotors 3 and 4 spin prograde and hold plus 50 percent. The industrial rotor beyond the momentum bay spins retrograde and holds minus 4 percent, cancelled by the momentum rings in the bay. The net is zero. Retrograde pair Prograde pair Rotors 1 and 2 Rotors 3 and 4 1234 −25%−25% +25%+25% Industrial rotor −4% Momentum rings +4% −50% +50% Industrial plus rings: 0 Net angular momentum: zero Aft on the left. Percentages are shares of the four-rotor total, spin seen from the spaceport end.
Rotors 1 and 2 hold minus 50 percent, rotors 3 and 4 plus 50 percent. The small remainder of Ehricke (the industrial rotor) is cancelled in the momentum bay.

With the pairs balanced, steering the station by one degree per day takes about 4 kN, for a day to start the turn and a day to stop it. Without pairing it takes 4.5 MN. The pairs make steering about a thousand times cheaper. Established physics

All four rotors turn at the same rate and give the same 1 g. The only difference a resident can find is the direction of the Coriolis push, which points opposite ways in the two pairs. The ascender cabins lean opposite ways too.

Open in the simulation: Momentum overlay Open in the simulation: Rotational frame overlay Open in the simulation: Two spins, one steady station.

The whole station with the momentum overlay: minus 50 percent for the first two rotors, plus 50 percent for the second two, net zero.
The momentum overlay: the first two rotors hold minus 50 percent, the second two plus 50 percent, and the net is zero. The small remainder of Ehricke is cancelled by the momentum rings. Open this view in the simulation

The industrial rotor and the momentum rings

One more spinning body breaks the balance. The industrial rotor is 2,300 m in radius and 3,500 m long, and it turns once every 143 seconds. It spins the same way as rotors 1 and 2 and holds about 4 percent of the four-rotor total, 1.9 × 10¹⁶ newton-metre-seconds. Its outer edge has 0.45 g. Design value

That 4 percent is cancelled by two momentum rings in a stationary vacuum bay between rotor 4 and the industrial rotor. Each is a carbon-fibre-class loop 3,000 m in radius, spinning in the opposite sense to the industrial rotor with its rim moving at 1 km/s. Together the rings weigh about 7 million tonnes, about 0.35 percent of the station. Engineering challenge

The rings speed up and slow down as the industrial mass changes. Cargo arrives, ships leave, rotor inventories shift, and the control system trades momentum between the rings and the rotors. It holds the net total within 0.1 percent of the four-rotor total. Nothing is thrown away. Momentum moves from one machine to another and the cost is electricity, not propellant. Design value

Looking along the momentum control bay past the reaction ring machines in their vacuum housings toward the rotor 4 end wall.
The momentum control bay between rotor 4 and the industrial rotor, with the ring machines in their vacuum housings. Open this view in the simulation

Bearings at the seams

Rotors do not roll on wheels. Each one floats on magnetic bearings at both ends, with emergency catchers that never touch in normal operation. In the bearing gallery between rotor 4 and the industrial rotor, the two hubs turn against each other, one prograde and one retrograde. Engineering challenge

Between rotors 2 and 3 the end walls move past each other at 157 m/s in opposite directions, 313 m/s apart. No bridge can cross a gap like that. A stationary frame carries the utility trunks, and passengers cross by the axis: ascender to the hub, a spin-down through the spin lock, the spine, and a spin-up into the next rotor. Rotors in the same pair keep a fixed relative position, so passenger and freight bridges can cross the gap within a pair. Design value

Cutaway hub rings and bearings run across black space, with a grey rotor disc on the left and lattice trusses on the right.
Hub rings and bearings run across black space, with a grey rotor disc on the left.

What a resident notices

On the ground, nothing. Momentum is a bookkeeping problem for the axis. You meet it in three places: the closed end walls signed COUNTER-ROTATING, the bearing gallery with its two hubs turning opposite ways, and the momentum bay where the rings turn in their housings. The station still re-points slowly. Launches wait for scheduled windows rather than turning the station to suit one ship.

The interface between two rotor ends spinning opposite ways, with a stationary frame and seals between them.
The gap between Noordung and Bernal: two walls moving 313 m/s apart, a stationary service frame between them, and no bridge. Passengers cross through the spine. Open this view in the simulation

Try it

Move cargo, launch a ship or fill a rotor, and watch the ledger balance.

A ledger of angular momentum: rotors 1 and 2 at minus 50 percent, rotors 3 and 4 at plus 50 percent, the industrial rotor at about 4 percent, cancelled by the momentum rings, so the net is zero.

Go deeper: The numbers Established physics

Angular momentum of a spinning body is its moment of inertia times its spin rate. For a rotor with most of its mass near the rim:

L = I × ω ≈ m × r² × ω
Rotor: L = 3 × 10¹¹ kg × (2,500 m)² × 0.0626 rad/s = 1.17 × 10¹⁷ N·m·s
Four rotors, by magnitude: 4.7 × 10¹⁷ N·m·s
Industrial: L ≈ 1 × 10¹¹ kg × (2,070 m)² × 0.044 rad/s = 1.9 × 10¹⁶ N·m·s
Body Spin Share of the four-rotor total
Rotors 1 and 2 retrograde, 0.0626 rad/s minus 50%
Rotors 3 and 4 prograde, 0.0626 rad/s plus 50%
Industrial rotor retrograde, 0.044 rad/s minus 4%
Momentum rings prograde plus 4%
Net 0 (within 0.1%)

The rotor mass is a planning value. The industrial rotor's effective radius is 0.9 of its 2,300 m outer radius because its mass is not all at the rim.

Go deeper: Worked example: the cost of steering Established physics

Turning a body with angular momentum L at a rate Ω needs a torque of Ω × L. Steering at 1 degree per day is Ω = 0.01745 rad / 86,400 s = 2.02 × 10⁻⁷ rad/s.

Unpaired: τ = 2.02 × 10⁻⁷ × 4.7 × 10¹⁷ = 9.5 × 10¹⁰ N·m
Force at each end of a 21 km hull: F = τ / 21,000 m = 4.5 MN
Paired, net held well inside 0.1%: F ≈ 4 kN

Pairing cuts the force by a factor of 1,000. The remaining 4 kN is a tiny push for the station's thrusters and momentum rings.

An ascender also moves momentum. Each ascent hands the rotor about 2.1 × 10¹⁰ N·m·s, roughly 2 parts in 10 million of one rotor's total. A climbing cabin's partner descends on the same tower and takes the momentum straight back.

Go deeper: Sizing a momentum ring Established physics

A ring of mass m, radius r and rim speed v holds L = m × v × r. To hold 1.9 × 10¹⁶ N·m·s at r = 3,000 m and v = 1,000 m/s:

m = L / (v × r) = 1.9 × 10¹⁶ / (1,000 × 3,000) = 6.3 × 10⁹ kg
σ = ρ × v² = 1,600 kg/m³ × (1,000 m/s)² = 1.6 GPa

That is 6.3 million tonnes, or about 7 million tonnes with trim headroom, split between two rings of about 3.5 million tonnes each. Against the station's 2.05 billion tonnes, 7 million tonnes is 0.34 percent, about 0.35. The hoop stress ρv² sets the speed limit, because a faster rim would need a stronger material than carbon fibre.

Sources and further reading

Real-world sources

Concordia design documents

  • Concordia engineering specification, section 16, and the counter-rotation design note.